Math, asked by shallumittal1578, 11 months ago

Find sum
9+7+5+3+............to 14 terms

Answers

Answered by danielkshitijkumar75
0

Answer:-56

Step-by-step explanation:

Use Sn=n/2(2a+(n-1)d)

a=9

d=-2

Answered by Anonymous
28

Given :

Find sum

9+7+5+3+............to 14 terms

To find :

Sum up to 14 terms

Solution :

First term (a) = 9

common difference (d) = 5 - 7 = -2

number of terms (n) = 14

Putting the value of a , d and n in this formula

\implies\sf S_n=\frac{n}{2}(2a+(n-1)\times{d}

\implies\sf S_{14}=\frac{14}{2}(2\times{9}+(14-1)\times{-2})

\implies\sf S_{14}=7(18-13\times{(-2))}

\implies\sf S_{14}=7(18-26)

\implies\sf S_{14}=7\times{(-8)}

\implies\sf S_{14}=-56

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