Question

find sum and product of roots of the quadratic equation x square - 4_/3+9=0​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

${x}^{2} - 4 \sqrt{3} + 9 = 0$

$a = 1 \\ b = - 4 \sqrt{3} \\ c = 9$

$sum \: of \: roots \: = \frac{ - b}{a}$

$\frac{ - ( - 4 \sqrt{3)} }{1} = 4 \sqrt{3}$

$product \: of \: roots \: = \frac{c}{a}$

$\frac{9}{1} = 9$

$hence \: the \: sum \: of \: roots \: and \: product \: of \: \: roots \: are \: 4 \sqrt3 \: and \: 9 \: respectively.$