find sum and product of roots of the quadratic equation x2-4_/3x +9=0
Answers
Answered by
47
Hi ,
Compare x² - ( 4/3 )x + 9 = 0 with
ax² + bx + c = 0 ,
a = 1 ,
b = -4/3 ,
c = 9 ,
sum of the roots = - b/a
= - ( -4/3 )/1
= 4/3
product of the roots = c/a
= 9/1
= 9
I hope this helps you.
: )
Compare x² - ( 4/3 )x + 9 = 0 with
ax² + bx + c = 0 ,
a = 1 ,
b = -4/3 ,
c = 9 ,
sum of the roots = - b/a
= - ( -4/3 )/1
= 4/3
product of the roots = c/a
= 9/1
= 9
I hope this helps you.
: )
Answered by
20
Hii friend,
X²-(4/3)X +9 = 0
This equation is in the form of AX²+BX+C. where,
A = 1 , B= -4/3 and C = 9
We know that,
Sum of zeros = -B/A => -(-4/3) = 4/3
And,
Product of zeros = C/A => 9/1
HOPE IT WILL HELP YOU... :-)
X²-(4/3)X +9 = 0
This equation is in the form of AX²+BX+C. where,
A = 1 , B= -4/3 and C = 9
We know that,
Sum of zeros = -B/A => -(-4/3) = 4/3
And,
Product of zeros = C/A => 9/1
HOPE IT WILL HELP YOU... :-)
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