Question

Find sum and product of zeroes of the quadratic polynomial 72-X-X2​

Answer 1

Answer:

-24

Step-by-step explanation:

72-X-2X=0

3X=-72

X=-72/3

X=-24

Answer 2

Answer:

It is to be written as

-x^2 -x +72

a=-1, b= -1, c = 72

sum= -b/a =-(-1/-1)= -1

product = c/a

=72/(-1) = -72

Another method

factorise x^2+ x-72

=(x+9).(x-8)

x+9=0 gives one zero = -9

x-8=0 gives another zero = 8

So sum= -9+8 = -1

product = -9×8= -72