find sum of 10 terms of A.P. -1 , 1÷4 , 3÷2
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Answer:
- AP:-1,1÷4=0.25,3÷2=1.5
- Therefore,AP:-1,0.25,1.5
- a=-1,d=1.25,n=10S10=?
- Sn=n/2{2a+(n-1)d}
- S10=10/2{2×-1+(10-1)×1.25}
- S10=5{-2+9×1.25}
- S10=5{-2+11.25}
- S10=5{-9.25}
- S10=-46.25
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