Question

find sum of 2 digit natural numbers divisible by 6​

Answer 1

Step-by-step explanation:

two digit natural numbers divusible by 6 are

12 ,18,24,30 ............... 96

12+18+24+30+.............+96

first term= 12

common difference=6

96= 12+ (n-1)6

84=(n-1)6

14=(n-1)

n=15

sum of 15 terms

15/2[2×12 + 14×12]

15/2[24+168]

15/2(180)

15×60

800