Find sum of 24thvterns 5,8,11,14
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Answered by
3
heya !!
here is ur answer
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Given terms :- 5 ,8 ,11 ,14 ..
♦ the given terms are in AP because
A2-A1 =A3 -A2 = A4-A3
8 - 5 = 11 -8 = 14 - 11
3 = 3 = 3
d = 3
▶ sum of 24 terms is as follows ⤵
♦ Sn = n/2 [2a + (n- 1 ) d
♦ n = 24 ; a = 5 ; d = 3
substituting the Values in the formula..
• S24 = 24/2 [ 2*5 + ( 24 -1 ) 3 ]
• S24 = 24/2 [ 10 + (23) 3]
• S24 = 24/2 [ 10 +69]
• S24 = 12 [ 79]
• S24 = 948.
♦ sum of 24 terms of the given AP is 948.
============================
hope it helps u..!!
here is ur answer
============================
Given terms :- 5 ,8 ,11 ,14 ..
♦ the given terms are in AP because
A2-A1 =A3 -A2 = A4-A3
8 - 5 = 11 -8 = 14 - 11
3 = 3 = 3
d = 3
▶ sum of 24 terms is as follows ⤵
♦ Sn = n/2 [2a + (n- 1 ) d
♦ n = 24 ; a = 5 ; d = 3
substituting the Values in the formula..
• S24 = 24/2 [ 2*5 + ( 24 -1 ) 3 ]
• S24 = 24/2 [ 10 + (23) 3]
• S24 = 24/2 [ 10 +69]
• S24 = 12 [ 79]
• S24 = 948.
♦ sum of 24 terms of the given AP is 948.
============================
hope it helps u..!!
Answered by
1
Hey
Here is your answer,
First term, a = 5
Common difference,d=8-5
=3
n=24
Sn=n/2(2a+(n-1)d)
=24/2(2x5+(24-1)3)
=12(10+23x3)
=12(10+69)
=12x79
=948
Hope it helps u!!!
Mark brainliest please
Here is your answer,
First term, a = 5
Common difference,d=8-5
=3
n=24
Sn=n/2(2a+(n-1)d)
=24/2(2x5+(24-1)3)
=12(10+23x3)
=12(10+69)
=12x79
=948
Hope it helps u!!!
Mark brainliest please
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