Question

Find sum of 5 and 5 Who will give answer first will be the brainliest.

Answer 1

Answer:

10

Step-by-step explanation:

Answer 2

Answer:

Definitely a daunting problem.

We start by using [math]\frac{d e^x}{dx} = e^x[/math] alongside Taylor’s theorem to get [math]e^x = \sum_{i=0}^{\infty} \frac{x^i}{i!}[/math].

To compute this mysterious sum, we will use the Cauchy product for infinite series and see that [math]e^5 * e^5 = \sum_{i=0}^{\infty} \sum_{j=0}^{i} \frac{5^j 5^{i-j}}{j! (i-j)!} = \sum_{i=0}^{\infty} \frac{1}{i!}\sum_{j=0}^{i} 5^j 5^{i-j}\frac{i!}{j!(i-j)!} = \sum_{i=0}^{\infty} \frac{1}{i!} \sum_{j=0}^{i} 5^j 2^{i-j} \binom{i}{j}[/math].

Since we have the Binomial theorem, this is equal to [math]e^5 * e^5 = \sum_{i=0}^{\infty} \frac{(5+5)^i}{i!} = e^{5+5}[/math]. Numerically computing the quantity [math]e^5 * e^5[/math] gives us approximately [math]1000[/math] which is remarkably close to [math]e^{29.15e-23\pi}[/math], so I believe that is your answer, [math]5+5 \approx 29.15e-23\pi[/math].