Find sum of 6 term of gp 0.1,0.01,0.001
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Answer:
a = 0.1
r = 0.01/0.1 = 0.1 (r<1)
n = 6
sn = a(1 - r^n)/1 - r
s6 = 0.1[1 - (0.1)^6]/1 - 0.1
= 0.1[1 - (0.1)^6]/0.9
= [1 - (0.1)^6]/9
= 1/9[1 - (1/10)^6]
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