Question

find sum of 8,15,22,.......246​

Answer 1

This is in the form of an AP

where, a=8(1st number)

d=7 (d is common difference)

nth digit is 246

an=246

a+ (n-1)d=246

after substitution we get

n=35

so, 35th term is 246

so,sum of 35 terms is

$n \div 2(2a + (n - 1)d)$

after substitution we get sum is

4445

so the sum is 4445

Answer 2

Step-by-step explanation:

find the sum of 8,15,22,....246