Find sum of all 3 digit numbers which are divisible by 72, 80 and 120
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How do I find the sum of all 3-digit numbers which are divisible by 4?
The smallest 3-digit number divisible by 4 is 100 while the largest is 996.
The sum of all 3-digit number divisible by 4 is an exercise in an AP.
a = 100, d = 4,
996 = a+(n-1)d = 100 + (n-1)*4, or
249–25 = 224 = (n-1)
n = 225
S225 = (225/2)[2*100 + (225–1)*4]
= (225/2)[200+ 896]
= (225/2)*1096
= 12330o.
Answer :123300.
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