Question

find sum of all multiple of 4 lying between 32 and 246 ​

Answer 1

SOLUTION

TO DETERMINE

The sum of all multiple of 4 lying between 32 and 246

EVALUATION

We have to find the sum of all multiple of 4 lying between 32 and 246

The numbers multiple of 4 lying between 32 and 246 are 8 , 12 , 16 ,..., 244

This is an arithmetic progression

First term = a = 8

Common Difference = d = 4

Let there are n terms in the progression

So by the given condition

$\sf{8 + (n - 1) \times 4 = 244}$

$\sf{ \implies \: 4(n - 1) = 236}$

$\sf{ \implies \: (n - 1) = 59}$

$\sf{ \implies \: n = 60}$

So the required sum

$\displaystyle \sf{ = \frac{60}{2} \bigg(8 + 244 \bigg)}$

$\displaystyle \sf{ = 30 \times 252}$

$= 7560$

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Answer 2

Step-by-step explanation:

That's your answers ok of find sum