find sum of all natural numbers between hundred and 500 which are divisible by 7
Answers
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Given:
Natural numbers between 100 and 500
To find:
The sum of all natural numbers between 100 and 500 which are divisible by 7
Solution:
The sum of all natural numbers between 100 and 500 which are divisible by 7 is 17,157.
We can find the sum by following the steps given below-
We know that the natural numbers between 100 and 500 which are divisible by 7 forms an arithmetic progression.
The sequence formed is 105, 112, and so on till 497.
The common difference, d=7
The first term, a=105
The last term, l=497
The number of terms=(last term-first term)/common difference+1
=(497-105)/7+1
=57
The sum of terms in an A.P.=n/2(a+l)
=57/2(105+497)
=57/2×602
=57×301
=17,157
Therefore, the sum of all natural numbers between 100 and 500 which are divisible by 7 is 17,157.