find sum of all natural numbers exactly divisible by 11 lying between 1 and 580
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Answered by
9
AP 11, 22, 33.......572
An= a+ (n-1)d
572= 11 + (n-1) 11
561= 11n-11
572= 11n
n= 52
Sn = n/2 (a+l)
S52 = 52/2 (11+572)
= 26*583= 15158
An= a+ (n-1)d
572= 11 + (n-1) 11
561= 11n-11
572= 11n
n= 52
Sn = n/2 (a+l)
S52 = 52/2 (11+572)
= 26*583= 15158
garima9cr3:
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Answered by
6
there are 52 numbers that lies between 1 to 580 and are divisible by 11.
now,s=n/2[2a+(n-1)d]
so,s=52/2[2*11+(51)11]
s=15158 ans.......
now,s=n/2[2a+(n-1)d]
so,s=52/2[2*11+(51)11]
s=15158 ans.......
plzz mark as best
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