Find sum of all natural numbers from 1-100 . Which are divisible by 2 and 5
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the sum is equal to 550
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10 , 20 ,........................,90
a = 10
d= 20-10
= 10
tn = a + (n-1)d
90 = 10 + (n- 1) 10
80 = (n-1)10
n= 9
Sn = n/2(a+L)
= 9/2(10 +90)
= 9/2×100
= 9×50
= 450
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