Math, asked by djitsj, 11 months ago

Find sum of all odd numbers between 10 and 200. By arithmetic progression

Answers

Answered by playboy12
1

a = 11

d = 2

l = 199

n = ?

s = ?

l = a + (n - 1)d

199 = 11 + 2n - 2

199 = 9 + 2n

190 ÷ 2 = n

n = 95

s = 95/2 [2a + (n - 1)d]

s = 95/2[22 + 94 × 2]

s = 95/2 (22 + 188)

s = 95/2(210)

s = 95 × 105

s = 9975

Answered by KJB811217
3

Answer:

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