Question

Find sum of all two digit numbers that are divisible by 6[ this is a question from arithmetic progressions]

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

two digits numbers divisible by 6:

12=1+2=3

18=1+8=9

24=2+4=6

30=3+0=3

36=3+6=36

42=4+2=6

48=4+8=12

54=5+4=9

60=6+0=6

66=6+6=12

72=7+2=9

78=7+8=15

84=8+4=12

90=9+0=9

96=9+6=15