find sum of an AP n^2/1,n,n^2-1,.........up to n terms.
Answers
Answered by
0
Step-by-step explanation:
Given, S
n
=2n
2
+n
Now, a
1
=S
1
=2(1)
2
+1=3
a
2
=S
2
−S
1
=2(2)
2
+2−3=7
a
3
=S
3
−S
2
=[2(3)
2
+3]−[2(2)
2
+2]=21−10=11
a
4
=S
3
−S
3
=[2(4)
2
+4]−[2(3)
2
+3]=36−21=15 and so on.
Therefore the required AP is 3,7,11,15...
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3
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