Question

find sum of even terms from 2 to 100​

Answer 1

Answer:,4,6,…………………………..,100

Here, a=2 (First term)

d=2 (common difference)

l (an)=100 (last term)

an=a+(n-1)d

100=2+(n-1)2

100=2+2n-2

100=2n

n=100÷2

n=50

Sn=n÷2 (a+l)

S50=50÷2 (2+100)

=25×102=2550.

Sum of all even numbers from 2 to 100 is 2550

Answer 2

Answer:

first term =2 = a

last term =100 = an

second term =4= a2

difference =d =a2 - a1

=4-2 =2

d=2

an=a+(n-1)d

100 =2 +(n-1)2

100= 2+2n -2

100 =2n

n=50

the sum of even terms from 2 to 100

=sn =(n/2)(2a+(n-1)d)

( 50 /2 )( 2(2)+(50-1)2)

25 ×(4+49×2)

25(4+98)

25(102)

2550