find sum of first 13 terms of AP = -6,0,6,12
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Topic:- Arithmetic Sequence or Progression
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nishiu13:
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[tex]a = - 6.d = 6 \\ s13 = \frac{2}{n} (2a +( n - 1)d \\ = \frac{2}{13} (2( - 6) + (13 - 1)6 \\ = \frac{2}{13}( - 12 + 72) \\ = \frac13}{2} \times 60 \\ =
is my answer i hope is my correct answer
is my answer i hope is my correct answer
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