Math, asked by gautami73, 8 months ago

find sum of first 16 term of an A. P. 7,13,19,25.............​

Answers

Answered by tparakh2012
1

Answer:

S16 = 16/2 ( 2A + (N-1)D

=> 8 ( 14+15*6)

=> 8(104)

=> 832

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Answered by ojasvi01gupta
3

Answer:

832

Step-by-step explanation:

sum of an AP is given by  n/2*(2a + (n-1)d)

here n= 16

a = 7

d = 13-7

 = 6

sum = 16/2 * ( 2*7 + (16-1)6)

       = 8 * (14 + 15*6)

       = 8 * (14 + 90)

       = 8 * ( 104)

       =  832

Hope this helps!!

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