find sum of first 16 term of an A. P. 7,13,19,25.............
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Answered by
1
Answer:
S16 = 16/2 ( 2A + (N-1)D
=> 8 ( 14+15*6)
=> 8(104)
=> 832
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Answered by
3
Answer:
832
Step-by-step explanation:
sum of an AP is given by n/2*(2a + (n-1)d)
here n= 16
a = 7
d = 13-7
= 6
sum = 16/2 * ( 2*7 + (16-1)6)
= 8 * (14 + 15*6)
= 8 * (14 + 90)
= 8 * ( 104)
= 832
Hope this helps!!
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