Question

find sum of first 26 terms of the AP 1, 3, 5, 7 and so on​

Answer 1

Step-by-step explanation:

a= first term= 1

d=common difference = 3-1=2

Sn= n/2[2a+(n-1)d]

S26=13[2+50]

S26=676

Answer 2

Answer:

Step-by-step explanation:

Ap:1,3,5,7....

a=1

d= 3-1 = 2

n = 26

S26= n/2(2a+ (n-1)d)

= 26/2 (2 ×1 +(26-1) 2

= 13(2+(25)2

= 13 (2 + 50)

= 13×52

= 676

Therefore S26= 676

Hope this helps u!!!!?