Question

find sum of first 31 terms of ap whose nth term given by 3+2n/3​

Answer 1

Answer:

1271/3

Step-by-step explanation:

first term will be 3+2×1÷3=11//3 last term will be 3+2×31/3=71/3 common sum of terms is 31/2×(11/3+71/3)=31/2×(82/3)=31×41/3=1271/3

Answer 2

Answer:

i think it is the answer

Step-by-step explanation:

3+2n/3

let n=1,

3+2/3

a1=11/3

3+2*2/3

13/3

d=2/3

s31=31/2(2*11/3+30*2/3)

s31=31/2(22/3+20)

s31=31/2(22+60)/3

s31=(31*82)/6

s31=2542/6

s31=423.6