Find sum of first 35 terms of an A.P. -10, -4, 2, 8 …….
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the answer to your question is....
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Answered by
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Answer:
Here, The sum of first 35 terms in this A.P. is 3, 395.
Step-by-step explanation:
Here, As per our given question,
=First term(a)=(-10), Common difference(d)=6
Sum of first 35 terms =S35=n/2[2a+(n-1)×d (where n=35)
=35/2[2×(-10)+(35-1)×6]
=35/2[(-10)+34×6]
=35/2[(-10)+204]
=35/2[194]
=35/2×194
=35×97
=3, 395 (Answer).
Thank you.
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