Find sum of first 5 terms of the G.P 2, 8, 32,
Answers
Answered by
1
Answer:
Hope it will help you:-)
Step-by-step explanation:
Here a = 2
r = 8/2= 4
n = 5
Sn = a(rn^-1)/(r-1)
= 2(45 -1)/(4-1)
= 2(45 -1)/3
= 682
Hence the required sum is 682.
Answered by
0
Answer:
We have : a= 2 , r =8/2= 4 , n=5
S= a(r^n -1)/r-1 = 2(4⁵-1)/4-1
=2×255/3 = 510/3=170
hence, sum of first 5 terms of given GP is 170
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