Find sum of first 50 natural numbers.
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Answer:
S=1+2+3+4……….+50
It is an easy arithmetic progression
which we know it has a formula that calculates the sum : S= n/2 *[a1+an]
n= number of members (50)
a1= the first member(1)
an= the last member (50)
So S=50/2 *(50+1) = 25 *51
S=1275
Explanation:
Answered by
1
Answer:What is the sum of the first 50 natural numbers? This is a arithmetic sequence. n(n+1)/2=50(51)/2=2550/2=1275.
Explanation:
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