Question

Find sum of first 50 terms of AP. 6,10,14....​

Answer 1

Answer:

6,10,14.......

a = 6

d = 10 - 6 = 4

n = 50

Sn = n/2 [2a + (n - 1)d]

= 50/2 [2 x 6 + (50 - 1)4]

=28 [12 + 49 x 4]

=28(12 + 196)

=28 x 208

=5824

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Sum of n terms=a(n×n+1/2)+bn

a means common difference here that Is 10-6 is 4

n means no. of term that is 50

b is f-a means first term - common difference =6-4=2

sum of first 50 terms of this sequence is ,

4× 50×51/2 +2×50

= 4×1275 + 100

=5200

sum of first 50 terms of this sequence is 5200

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