find sum of first n numbers of term
Attachments:
Answers
Answered by
0
Answer:
n+2n^
Step-by-step explanation:
a=3,a2=7,a3=14,a4=27,a5=52
d=a2-a1=7-3=4
Sn =n/2(2a+(n-1)d
=n/2(2×3+(n-1)4
=n/2(6+4n-4)
=n/2(2+4n)
=n/2×2(1+2n)
=n(1+2n)
=n+2n^
iamrohan03S:
it is not in AP see cere fully the difference between those sum are different
Answered by
0
if it is not an AP , then sum of first n no. of term can't be find out .
prove it wrong if you can
ok tomorrow
okkkk
sorry I made a mistake in last line it should be = 3×(1+2^2+2^3+2^4+....nth term)+(1+2+3+4+5+....n-1 th term)= 3×(2^n-1)+n(n-1)/2
Similar questions