Find sum of integers between 100 and 200 that are not divisible by 9
Answers
Answered by
1
108,117,126.......198 and so on
so a=108
l=198
n=?
nth term= a+(n-1)d
198=108+(n-1)9
198=108+9n+9
198-99=9n
99=9n
99/9=n
n=11
Now, sum of n terms
sum of first 11terms= 11/2(108+198)
=11/2(306)
=11×153
=1683
Similar questions