Question

find sum of last 10 terms of AP : 4,8,12....,240​

Answer 1

Answer:

n=4

A2-A1

equal to 8 - 4 is equal to 4

a n is equal to N plus and Nminus 1 into d

=240 is equal to 4 plus (4-1)×4

=60=16-4

=60/12

=5

Answer 2

Answer:

let a be the first term and d be the common different

then, a=4 and d=240-4 =236

an= a+( n - 1 ) d

a10= 4 + ( 10 - 1 ) 236

a10= 4+ 9 × 236

a10= 4+2124

a10=2128