find sum of multiples of 7 from 100 to 1000
Answers
Answered by
3
a = 105 , an=994 , d = 7
an=a +(n-1)d
and solve it for n
if u need elaboration just ask for it in comment
and use that n in formula
sn= n/2 (a+an)
an=a +(n-1)d
and solve it for n
if u need elaboration just ask for it in comment
and use that n in formula
sn= n/2 (a+an)
Answered by
3
Ans.
The sequence of multiples of 7 is
105, 112, ... , 994.
First term (a1) = 105,
2nd term (a2) = 112,
. . . . .
. . . . .
. . . . .
n-th term (an) = 994.
Common difference (d) = 7.
So, n-th term = a1 + (n-1)d
or, 994 = 105 + 7(n-1)
or, 7n = 896
or, n = 128.
Therefore the sum is
= a1 + a2 + a3 + ... + an
= (n/2)(a1 + an)
= 128.(105 + 994)
= 128 × 1099
= 140672.
☆I HOPE THAT THIS HELPS YOU.☆
The sequence of multiples of 7 is
105, 112, ... , 994.
First term (a1) = 105,
2nd term (a2) = 112,
. . . . .
. . . . .
. . . . .
n-th term (an) = 994.
Common difference (d) = 7.
So, n-th term = a1 + (n-1)d
or, 994 = 105 + 7(n-1)
or, 7n = 896
or, n = 128.
Therefore the sum is
= a1 + a2 + a3 + ... + an
= (n/2)(a1 + an)
= 128.(105 + 994)
= 128 × 1099
= 140672.
☆I HOPE THAT THIS HELPS YOU.☆
Swarup1998:
Can u add my answer as Brainliest?
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