Question

Find sum of no between 200 to 300 which divisible by 3

Answer 1

Answer: 7760

Explanation: Between 200 and 300, the first and last number that is divisible by 3 is 201 and 297 respectively.

Therefore the number of terms divisible by 3 between 200 and 300 is

(297-201)/3 = 32

Formula of sum of an AP is [n(2a+(n-1)d)]/2.

Here, ATP, n=32, a = 201, d = 3.

Putting values. [32*(2*201+(32-1)*3]/2 = 16*(402+93)

                                                                  =  7760.