Find sum of the 9th term of AP is 5 10 15
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Answer:
Sum of first 9 terms of the arithmetic sequence = 225
Step-by-step explanation:
Arithmetic sequence = 5, 10, 15, 20...
Common difference (d) = x₂ - x₁ (second term - first term)
= 10 - 5 = 5
x₉ = x₁ + 8d = 5 + 8 × 5 = 40 + 5 = 45
Sum of first 9 terms of the arithmetic sequence = 1/2n(x₁ + x₉)
= 1/2 × 9 ( 5 + 45)
= 9/2 × 50
= 9 × 25
= 225
∴ The sum of first 9 terms of the arithmetic sequence 5, 10, 15... is 225.
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