Find sum of the series of n terms (1^3)/1+(1^3+2^3/)1+3 + (1^3+2^3+3^3)/1+3+5 +.......
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Answer:
23/4.
Step-by-step explanation:
1^3/1 +(1^3+2^3)/1+3 + (1^3+2^3+3^3)/1+3+5.
= 1/1 + 1+1+1/4 + 1+8+27/9
= 1/1 + 3/4 + 36/9 ( taking lcm)
= 4+3+16/4
= 23/4
this is your answer.And if you want it with infinite times then you can multiple it with infinity.
I hope it will be helpfull for you
hope it will be helpfull for you dear
hope it will be helpfull for you dear mark as brainliest
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