Find sum of three consecutive multiples of 3 and 36& find the numbers
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Answer:The greatest of the three numbers is 15.
The other two numbers are 9 and 12.
Explanation:
The three consecutive multiples of 3 can be written as;
x , x + 3 and x + 6 with x + 6 being the greatest.
We know from the problem the sum of these three numbers equal 36 so we can write and solve for x through the following:
x + x + 3 + x + 6 = 36
3 x + 9 = 36
3 x + 9 − 9 = 36 − 9
3 x = 27
3 x/3= 27/ 3
x = 9
Because we are looking for the largest we must add 6 to x to obtain the largest number:
6 + 19 = 15
Please mark as the brainliest answer,,,,,
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