Question

find sum of (x-y)²+(x²y²)+(x+y)²+..............[(x+y)²+6xy)]

Answer 1

Answer:

Step-by-step explanation:

Hey there !!!!

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  x+y=12 ------Equation 1

Squaring equation 1 on both sides 

 (x+y)² = 12²-----Equation 2

(a+b)²=a²+2ab+b²

Now comparing (x+y)² with (a+b)² here a=x and b=y 

So Equation 2 becomes 

 (x+y)² = 12²

 x²+2xy+y² =12²

 x²+y² = 144 - 2xy----Equation 3

But in question its given that xy= 32 

So, substituting xy = 32 in equation 3

  x²+y² =144-2*32

 x²+y² =144-64 = 80.

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Hope this helped you........................

x+y = 12. ---(1)

xy= 32

Squaring eq 1 both side we get

(x+y)^2 = 12^2

x^2 + y^2 + 2xy = 144. ---(2)

Putting the value of xy in eq 2

x^2 + y^2+2×32 = 144

x^2 + y^2 = 144-64

x^2 + y^2 = 80

I think it is helpful for u

Gd luck.. ☺

Answer 2

Answer:

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no

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