Find sum of zeros of polynomial X square + 7 x + 10
Answers
Answered by
3
x2+7x+10
x2(5+2)x+10
x2+5x+2x+10
x(x+5)+2(x+5)
(x+2)(x+5)
let the zeroes be € and ¥
so €= -2
¥= -5
compare the above equation by ax2+bx+c
a=1, b=7, c=10
sum of zeroes = €+¥
-2+(-5)
-7
x2(5+2)x+10
x2+5x+2x+10
x(x+5)+2(x+5)
(x+2)(x+5)
let the zeroes be € and ¥
so €= -2
¥= -5
compare the above equation by ax2+bx+c
a=1, b=7, c=10
sum of zeroes = €+¥
-2+(-5)
-7
Answered by
2
Hey mate !!
Here's the answer !!
Equation = x² + 7x + 10 = 0
Factorising the equation we get,
= x² + 2x + 5x + 10 = 0
= x ( x + 2 ) + 5 ( x + 2 ) = 0
=> ( x + 5 ) ( x + 2 ) = 0
=> x = - 2 , - 5
So sum of zeros are ( - 2 ) + ( - 5 )
= ( - 2 ) - 5
= - 7
Hope my answer helps !!
Cheers !!
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