Find sum to the infinity of 1,3/2,5/4,7/8, 9/16,...
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Step-by-step explanation:
a= 1
d= 1/2
Sn=?
Sn.= n/2[2a+(n-1)d]
Sn = n/2[2×1+(n-1)1/2]
Sn = n/1[2+n/2-1/2]
Sn = n/2[3/2+n/2]
Sn = n/4[n+3]
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