Question

find surface area (A) of a cylinder height=15m, radius=6m
formula A=2πr(h+r)

Answer in rough copy
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Answer 1

Answer:

formula= 2πr(h+r)

2×22/7×6(15+6)

44×6/7(21)

44×6×3

=792

Answer 2

Given: The height of cylinder is 15m and radius is cylinder is 6m.

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Need to find: Surface area of cylinder.

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⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

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We know that, if we are given with the height of cylinder & radius of cylinder, we have the required formula, that is,

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$\sf{: \implies Surface \: area_{(cylinder)} = 2\pi r\big\lgroup h + r\big\rgroup}$

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⠀⠀⠀ Here, the value of π is 22/7, r is the radius of cylinder & h is the height of cylinder. And here in this question we have the values of height of cylinder and radius of cylinder, that is, h = 15m & r = 6m. So, by using the required formula, we can get our required answer.

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By using the required formula and substituting all the given values in the formula, we get:

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$\sf{: \implies Surface \: area_{(cylinder)} = 2 \times \dfrac{22}{7} \times 6 \big\lgroup15 + 6 \big\rgroup} \\ \\ \\ \sf{: \implies Surface \: area_{(cylinder)} = 2 \times \dfrac{22}{ \cancel{ \: 7 \: }} \times 6 \times \cancel{21}} \\ \\ \\ \sf{: \implies Surface \: area_{(cylinder)} =2 \times 22 \times 6 \times 3} \\ \\ \\ \sf{: \implies Surface \: area_{(cylinder)} = 44 \times 6 \times 3} \\ \\ \\ \sf{: \implies Surface \: area_{(cylinder)} = 264 \times 3} \\ \\ \\ \sf{: \implies \boxed{\frak{\pink{Surface \: area_{(cylinder)} = 792}}}}$

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∴ The surface area if cylinder is 792m².