Question

Find t for which the vectors 2i - 3j + k, i + 2j - 3k and j - tk are coplanar.

Answer 1

Answer:

The required answer is   " t = 1 "

Step-by-step explanation:

The vectors 2i - 3j + k, i + 2j - 3k and j - tk will be Co-planar if their Scalar Triple Product is equal to ZERO.

so we have

$\left[\begin{array}{ccc}2&-3&1\\1&2&-3\\0&1&-t\end{array}\right]=0\\\\\\2(-2t+3)-(-3)(-t-0)+1(1-0)=0\\-4t+6-3t+1=0\\-7t+7=0\\-7t=-7\\t=1$