Question

find t volume occupied by 44g of carbondioxide at NTP​

Answer 1

Answer:

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Explanation:

As given,

Mole =

Molar mass

mass

=

44

4.4

=0.1

V

CO

2

=n×Molar volume=0.1×22.4=2.24 L

Answer 2

Molecular weight of CO2 = 44.

So 44 g of CO2 will occupy=

22.4 L at NTP.