Find T when the bob reaches the bottom most point
Length = 1.5m
Angle with vertical = 60°
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Initial kinetic energy Ki = 0 because the ball is released from rest.
Final potential energy Uf = 0 by definition.
Conclusion: Ui = Kf or mgh = ½ mvf2,
where h is the height from which the ball is released.
Cancel the m's to give: vf = (2gh)½
Determine h from geometry: h = L - Lcos θ = L (1-cos θ)
With L = 1.40 m and θ = 20o, h = 0.0844 m, vf = (2gh)½ = 1.29 m/s
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