Question

find t11 for following a.p and then find 30th term of a.p .3,8,13,18​

Answer 1

Answer:

t11=53 and 30th term = 148

Step-by-step explanation: I used term 't' as 'a'

Answer 2

Answer:

$\huge{\boxed{\boxed{\sf{t11=53\:and\:a30=148}}}}$

Step-by-step explanation:

$\huge{\boxed{\boxed{\underline{\sf{SOLUTION-}}}}}$

□a=3

□d=a2-a1=8-3=5

To find:

○t11=?

○a30=?

$t11 = a + 10d \\ = )3 + 10 \times 5 \\ = )3 + 50 \\ = )53$

□t11=5

$a13 = a + 29d \\ = )3 + 29 \times 5 \\ = )3 +145 \\ = )148$

□a30=148

$\huge{\boxed{\boxed{\sf{t11=53\:and\:a30=148}}}}$