Question

find t11 of the A.P. 4,9,14,....

Answer 1

Here first term (a) = 4 and common difference(d) = 5
So 11th term = a+10d = 4+10*5 = 50+4 = 54
54 is 11th term of this A.P

Answer 2

1st term= 4
2nd term= 9
common difference= 9-4=5
nth term= a+(n-1)d
             = 4+(11-1)5
             = 4+50
              =54