Question

find T25 of the AP 12 16 20 24 ,..........​

Answer 1

Step-by-step explanation:

a=12

d=16-12=4

T25=a+(n-1)d

=12+24*4

= 12+96

= 108.

Answer 2

Answer:

heya mate there's your answer

Given series 12,16,20,24...............

let first term of the AP T1=12

second term of the AP be T2 =16

common difference of the AP be d

we know that d=T2-T1

d=16-12

d=4

so common difference of the AP is 4

nth term of an AP is,

Tn=T1+(n-1)d

Now, T25=T1+(25-1)d

=12+24(4)

=12+96

=108

So T25 =108

hope it helps you

Thank you