Question

Find-

tan(Φ-14π)


Explanation required​

Answer 1

Tan (2nπ+theta)= tan theta where n is an integer

tan (-14π+theta)= tan (2*-7*π+theta)=tantheta

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Answer 2

Solution

==>

tan ( @ - 14π)

Note => theta = @

As we know that

tan ( A - B ) =

(tan A - tan B)/1+ tan A.tanB

So , putting the value of A and B as given in the question.

tan ( @ -14π) =

[tan @ - tan(14π)]/1- tan@ tan(14π)

Now finding the value of tan 14π

tan(14π)=>

tan( 7×2π + 0)

Hence,

tan 0 = 0 = tan 14π

Now

tan(@-14π). =. tan @ - tan 0 / 1 - tan @ tan 0

tan(@- 14π) = tan @ / 1

tan ( @ - 14π) = tan @

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