Find tan B if a=5 and c=12 a(5√119)/11 b. (5)/√119 c. √119/5 d. √119/119
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Given : a=5 and c=12
To Find : Tan B
5√119
(5)/√119
√119/5
√119/119
Solution:
Triangle ACB right angled at C
Tan B = AC/ BC
=> Tan B = b/a
a = 5
c = 12
c² = a² + b²
=> 12² = 5² + b²
=> 144 = 25 + b²
=> b² = 119
=> b = √119
Tan B = √119/5
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