Question

find tangent of curve y^2-7x-8y+4=0 at point (2,0)​

Answer 1

Answer:

hello

Step-by-step explanation:

y²-7x - 8y + 4 =0

(0)² - 7(2) - 8(0) + 4 =0

0 - 14 - 0 + 4 = 0

-10 = O

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