find tbe least number which divided by 6 , 15 , and 18 .leave remainder 5 in each case
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Answer:
95
Answer: To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number. Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case
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it is good question
very good
Step-by-step explanation:
I will send the answer in comment section ok
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