Question

find tbe value of polynomial xsquare+2x+5 x=root3

Answer 1

Hey mate thank fir the question
Hope it helps
g=root3
=x^2+2x+5
$( \sqrt{3} {?}^{2} ) + 2 \times \sqrt{3 } + 5$
=
$3 + 2 \sqrt{3} + 5$
=
$8 + 2 \sqrt{3}$

Answer 2

$\large{\bold{\boxed{Solution:}}}$

Putting x = √3 in $x {}^{2} + 2x + 5$

we get;

$x {}^{2} + 2x + 5 \\ \\ ( \sqrt{3} ) {}^{2} + 2 \times \sqrt{3} + 5 \\ \\ 3 + 2 \sqrt{3} + 5 \\ \\ 8 + 2 \sqrt{3}$

$\large{\bold{\boxed{Thank you!!}}}$